*There is a certain number if sorted arrays and each of them contains numbers. We want to take an element from every array in such a way, that the difference between the elements is the lowest.*

For simplicity let’s say N=3 and the arrays are like:

A = {4, 10, 15, 20}
B = {1, 13, 29}
C = {5, 14, 28}

Now we need to choose one element from each of array, let’s call them a, b, c, such that |a – b| + |b – c| + |c – a| is minimal. For this case the solution is a = 15, b = 13, c = 14. But how to find it?

For solving the problem we are going to use minimal heap data structure with constant size. In our case the size of the heap is equal to number of arrays we process, so the size = 3. In the first step we take the minimal element from the array, and we store the difference of its sum. Now we are going to remove the element from the top of the heap and replace it with the next element from the array the removed element comes from. Inserting the a new element into the heap will rearrange the elements so that the minimal one will be always on the top. We store again the new difference if it’s smaller than the previous one and we repeat until one of the arrays becomes empty. Let’s take a look at an example:

H = {1, 4, 5}, diff = 8
we remove 1 and put 13 as 1 belonged to the same array
H = {4, 5, 13}, diff = 18
we remove 4 and put 10 as 4 belonged to the same array
H = {5, 10, 13}, diff = 16
we remove 5 and put 14 as 5 belonged to the same array
H = {10, 13, 14}, diff = 8
we remove 10 and we put 15 as 10 belonged to the same array
H = {13, 14, 15}, diff = 4
...

I was inspired to describe this solution, that is called k-way merged, after meeting several questions related to it on careercup – but without a very easy explanation. I hope it helps a bit. Actually it helps at least me ðŸ™‚

Best Regards

Joe Kidd

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